Ans :
(Interviewer told syntax doesn't matter, write pseudo-code type program)
1. Not using direct function.
void main()
{
int i, j, a, n, number[30];
printf("Enter the value of N \n");
scanf("%d", &n);
printf("Enter the numbers \n");
for (i = 0; i < n; ++i)
scanf("%d", &number[i]);
for (i = 0; i < n; ++i)
{
for (j = i + 1; j < n; ++j)
{
if (number[i] > number[j])
{
a = number[i];
number[i] = number[j];
number[j] = a;
}
}
}
printf("The numbers arranged in ascending order are given below \n");
for (i = 0; i < n; ++i)
printf("%d\n", number[i]);
}
2. If we write in swift using higher order function, then
var numbers = [45,6,113,56,8,56,43,78]
print(numbers.sort()) //Sorting in Ascending order
print(numbers.sort(>)) //Sorting in Descending order
Interviewer mostly asked this question to check your programming logic. So he/she don't require syntax.
Q. Sorting strings array
A.
Method 1 :
var sortedArray = swiftArray.sorted { $0.localizedCaseInsensitiveCompare($1) == ComparisonResult.orderedAscending }
Method 2 :
let sortedNames = names.sort { $0.name < $1.name }
let sortedNames = names.sorted(by: <)
(Interviewer told syntax doesn't matter, write pseudo-code type program)
1. Not using direct function.
void main()
{
int i, j, a, n, number[30];
printf("Enter the value of N \n");
scanf("%d", &n);
printf("Enter the numbers \n");
for (i = 0; i < n; ++i)
scanf("%d", &number[i]);
for (i = 0; i < n; ++i)
{
for (j = i + 1; j < n; ++j)
{
if (number[i] > number[j])
{
a = number[i];
number[i] = number[j];
number[j] = a;
}
}
}
printf("The numbers arranged in ascending order are given below \n");
for (i = 0; i < n; ++i)
printf("%d\n", number[i]);
}
2. If we write in swift using higher order function, then
var numbers = [45,6,113,56,8,56,43,78]
print(numbers.sort()) //Sorting in Ascending order
print(numbers.sort(>)) //Sorting in Descending order
Interviewer mostly asked this question to check your programming logic. So he/she don't require syntax.
Q. Sorting strings array
A.
Method 1 :
var sortedArray = swiftArray.sorted { $0.localizedCaseInsensitiveCompare($1) == ComparisonResult.orderedAscending }
Method 2 :
let sortedNames = names.sort { $0.name < $1.name }
let sortedNames = names.sorted(by: <)